2cos^3(x)+cos^2(x)-5cos(x)+2=0

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Solution for 2cos^3(x)+cos^2(x)-5cos(x)+2=0 equation:


Simplifying
2cos3(x) + cos2(x) + -5cos(x) + 2 = 0

Multiply cos3 * x
2cos3x + cos2(x) + -5cos(x) + 2 = 0

Multiply cos2 * x
2cos3x + cos2x + -5cos(x) + 2 = 0

Multiply cos * x
2cos3x + cos2x + -5cosx + 2 = 0

Reorder the terms:
2 + -5cosx + cos2x + 2cos3x = 0

Solving
2 + -5cosx + cos2x + 2cos3x = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -5cosx + cos2x + -2 + 2cos3x = 0 + -2

Reorder the terms:
2 + -2 + -5cosx + cos2x + 2cos3x = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -5cosx + cos2x + 2cos3x = 0 + -2
-5cosx + cos2x + 2cos3x = 0 + -2

Combine like terms: 0 + -2 = -2
-5cosx + cos2x + 2cos3x = -2

Reorder the terms:
2 + -5cosx + cos2x + 2cos3x = -2 + 2

Combine like terms: -2 + 2 = 0
2 + -5cosx + cos2x + 2cos3x = 0

The solution to this equation could not be determined.

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